Apology for the low resolution, but during a PsiQuantum talk, the team mentioned that 2-qubit gates are cheap in fault-tolerant design but T gate is very expensive, whereas 2-qubit gates are noisy in NISQ design but single-qubit gate is very cheap. Why is this the case?
Why are 2-qubit gates cheap in fault-tolerant design but T gate is very expensive?
- 1 reply
- last reply by quantumnoob Dec. 22, 2021
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Fault-tolerant design typically consists of Clifford and T gates. Implementing the T gate requires a step called magic state distillation (The underlying logic here is that the T gate is not transversal and thus less resource-efficient) which takes relatively more resources than 2-qubit gates.
For details, you could check Quantum 5, 396 (2021).
